x^2-8x+16=96

Solution for x^2-8x+16=96 equation:

x^2-8x+16=96

We move all terms to the left:

x^2-8x+16-(96)=0

We add all the numbers together, and all the variables

x^2-8x-80=0

a = 1; b = -8; c = -80;
Δ = b2-4ac
Δ = -82-4·1·(-80)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8\sqrt{6}}{2*1}=\frac{8-8\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8\sqrt{6}}{2*1}=\frac{8+8\sqrt{6}}{2}
$